The squared-term discovery
KE = ½ × m × v² kinetic energy (J) = ½ · mass (kg) · speed² (m/s)²
A 2 kg cart at faster and faster speeds. Fill in the kinetic energy column —
the first row is done — then find the pattern before anyone tells it to you.
| Speed v (m/s) | v² | KE = ½ · 2 · v² (J) |
|---|---|---|
| 1 | 1 | 1 |
| 2 | ||
| 3 | ||
| 4 | ||
| 5 |
-
Double the speed (1 → 2 m/s) and the kinetic energy multiplies by ___. Triple it (1 → 3) and KE multiplies by ___. Write the rule: "KE grows with the ___ of speed."
-
You met this pattern before — the stopping-distance ×4 rule in the Newton's laws unit. In one sentence: why does a car need 4× the room to stop from twice the speed?
The beetle shelf: PE = mgh
PE = m × g × h potential energy (J) = mass (kg) · 9.8 · height (m)
Our mascot (mass 0.02 kg — a chunky 20 g) climbs the shelf. Gravity never sleeps.
Beetle on the low shelf, 0.5 m up. Stored PE?
Beetle on the top shelf, 1.5 m up. Stored PE? How many times bigger than the low shelf — and why is it exactly that factor?
Now a 1 kg textbook on a 2 m shelf. PE? Who stores more energy per meter climbed — and what does that tell you about where the mgh formula "hides" the danger of high shelves?
Bookkeeping: every joule somewhere
A coaster car starts at the top with 100 J of potential energy. On the way down, energy moves between accounts — but the total must always be 100 J. Fill in the missing entries of the ledger.
| Position | Potential | Kinetic | Heat (friction) | Total |
|---|---|---|---|---|
| Top of hill | 100 | 0 | 0 | 100 |
| Halfway down | 50 | 2 | 100 | |
| Bottom | 0 | 18 | 100 | |
| After the flat run-out | 0 | 30 | 100 |
-
The 18 J of "heat" at the bottom — the energy didn't vanish. Where did it go, physically? One sentence.
-
At the end of the ride the car stops. Write the final row of the ledger yourself (all 100 J accounted for).
The First Hill Rule, as a word problem
A coaster's lift hill is 40 m tall. The cars carry no engine — the lift hill's PE is all the energy they'll ever get. Friction costs the ride 20% of its energy before the second hill.
-
Only 80% of the energy survives. In "energy-height" terms, that's like starting from an effective height of 40 × 0.80 = ___ m.
-
The second hill is 35 m tall. Does the car make it over? Show the comparison that decides it.
-
State the First Hill Rule as an inequality a roller-coaster designer could tape to the wall: "height of any later hill must be ___ than (1 − friction loss) × height of the first hill."
Answer key — teachers
Part A
v=2: 4, 4 J · v=3: 9, 9 J · v=4: 16, 16 J · v=5: 25, 25 J.
- ×4, ×9 — "KE grows with the square of speed."
- Stopping means bleeding off kinetic energy; twice the speed = 4× the KE = 4× the energy the brakes must turn into heat = 4× the distance.
Part B
- PE = 0.02 × 9.8 × 0.5 = 0.098 J
- 0.02 × 9.8 × 1.5 = 0.294 J — exactly 3× because height tripled and PE is proportional to h.
- 1 × 9.8 × 2 = 19.6 J — mass is the quiet multiplier; heavy things up high are the dangerous ones (≈200× the beetle's per-meter energy).
Part C
Halfway: KE = 48 J · Bottom: KE = 82 J · Run-out: heat = 70 J.
- Friction turned it into heat in the wheels, track, and air — moved, not lost.
- PE 0, KE 0, heat 100, total 100.
Part D
- 32 m
- No — 32 m of effective energy < 35 m of hill; the car stalls and rolls back.
- "…must be less than (1 − friction loss) × first-hill height."